Hi Raj,

I think u made a mistake in find pattern... i.e. you should have used \1 and not $1.

But in replace pattern we can use either \1 or $1.

$input='<it>a</it>+2<it>b</it><inf><it>cd</it></inf>
<it>a</it>+2<it>b<sup>cd</sup></it>';

$input=~s!</it><(.*?)><it>(.*?)</it></\1>!<\1>$2</$1></it>!sg;
print "\n$input";

[download]

Thanks,

Gopal.R

In reply to Re: using $1 as find string by gopalr
in thread using $1 as find string by texuser74

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