you only need to find one displacement vector

Ah yes, this is true. Nice idea. I'll use this as well, thanks.

you won't really need to use sine/cosine, just tangent

But there's no builtin tangent function, which means I'll either have to use Math::Trig, or roll my own tan, in terms of sin and cos anyway, right? Or is there something I'm missing?

In reply to Re^2: Code refactoring: simple trig, but it's been so long. by revdiablo
in thread Code refactoring: simple trig, but it's been so long. by revdiablo

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