Why should that 2 be a 5? Saying $#ary2 will give you the index of the last array element, in this case 2. I've never seen anywhere that says $# should return the value of the last element. This makes perfect sense with the use of scalar(@ary2) as well. Witness:
scalar(@ary2) == $#ary2 - $[ +1
scalar(@ary2) == 2      - 0  +1
scalar(@ary2) == 3
            3 == 3

[download]

Makes sense to me.

Guildenstern
Negaterd character class uber alles!

In reply to (Guildenstern) RE: Arrays: Last-index special variable vs. scalar values by Guildenstern
in thread Arrays: Last-index special variable vs. scalar values by mwp

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