Please note that: 

$foo = shift || 1;
# is the same as
$foo = (shift || 1);

[download]
and 
$foo = shift or 1;
# is the same as
($foo = shift) or 1;

[download]

see perldoc perlop about Operator Precedence

In reply to Re: fun(?) with += by ccn
in thread fun(?) with += by Anonymous Monk

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