Is there any danger in doing something like this? 

$temp = defined($temp = &func()) ? $temp : 'undefined';

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When I say 'danger', I'm wondering if I may be surprised at my result due to the order of evaluation being different than I expect.

By the way, my motivation for this is to either save a little space by not declaring an extra variable: 

$temp1 = &func();
$temp2 = defined($temp1) ? $temp1 : 'undefined';

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or to save a little time by not calling func twice: 
$temp = defined(&func()) ? $func() : 'undefined';

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In reply to Safe to use ternary operator like this? by Anonymous Monk

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