I've ended up with this for now.
cat shafile | perl mkvectors.pl 
set_mask();

while (<STDIN>) {
    chomp;
    $in = substr($_, 0, 40);
    if ($in =~ /^[0-9a-f]/i ) { # check that it's valid hex
        my $in_bits = unpack("B*", pack("H40",$in));
        my %offsets ;
        for(my $j=0;$j<20;$j++) {  # each of 20 bitmasks
          $offsets{calc_vector($in_bits,$bits[$j])} = 1;
        } 
        foreach my $k (sort {$a <=> $b} (keys %offsets) ) {
            print "$k\n";
        }
    }
}

print "\n";

exit;

#--------

sub set_mask
{
    $mask[0]="FFFF804020100804020100804020100804000102";
    $mask[10]=reverse($mask[0]);
    $bits[0] = unpack("B*", pack("H40",$mask[0]));
    $bits[10] = unpack("B*", pack("H40",$mask[10]));
    for (my $i=1;$i<10;$i++) {
        $mask[$i] = substr($mask[$i-1],36,4) . substr($mask[$i-1],0,36
+) ;
        $mask[10+$i] = substr($mask[10+$i-1],36,4) . substr($mask[10+$
+i-1],0,36)
 ;
        $bits[$i] = unpack("B*", pack("H40",$mask[$i]));
        $bits[10+$i] = unpack("B*", pack("H40",$mask[10+$i]));
    }
    return(0);
}

sub calc_vector {
my $input = shift;
my $mask = shift;
my $vecs = "";

    for (my $i=0;$i<160;$i++) {
        if (substr($mask,$i,1) eq "1") {
            $vecs .= substr($input,$i,1);
        }
    }

    return(hex(unpack("H*", pack("B32",$vecs))));
}

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In reply to Re: bitmask to vector problem by dwhite20899
in thread bitmask to vector problem by dwhite20899

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