Er, the exact same reason: 
Foo::Bar::Baz->new()

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works. Perl just needs a package name as a string to look up the appropiate method, it doesn't care if the string is in the form of a bareword or contained in a scalar.

In reply to Re: $foo = "Foo::Bar"; $foo->new() works? by BUU
in thread $foo = "Foo::Bar"; $foo->new() works? by mikfire

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