... you can use a scalar de-ref/ref: 
print "year is ${\((localtime)[5]+1900)}!\n";

[download]

True, but I've finally managed to get this mechanism excised from the FAQ because it is messy-looking and confusing.

Many people looking at the that code (including the authors of early versions of the FAQ) would expect the expression to be evaluated in a scalar context. It is not. The expression in \(EXPR) is evaluated in a list context. Not, of course, that this makes any difference for the + operator.

In reply to Re^4: Questions about context by nobull
in thread Questions about context by Anonymous Monk

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