I'm not sure I understand your question. The string you show, "1998073001003", already seems to be in YYYYMMDDhhmmss format.

If you want to extract the parts of that date, I reccomend simply using substr or unpack. Unpack would be faster but only works of the date fields are of constant width, which they appear to be.

In reply to Re: changing a string to a useable date time by friedo
in thread changing a string to a useable date time by cpiety

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