Which is why I initially mentioned that incrementing would be easy, to find the alternative. If the input isn't already palindromic, you have to find two palindromic alternatives. Roy Johnson wrote the code I foresaw: '10##'++ would be '1111'.

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[ e d @ h a l l e y . c c ]

In reply to Re^5: Challenge: Nearest Palindromic Number by halley
in thread Challenge: Nearest Palindromic Number by Limbic~Region

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