I.e. can you break the name of the scalar up and insert a number into it $Sel[1......80]Ttl so i can then use that in my additions.. ?
Yes, but the best way to do almost that it is to use an array: 
for my $number (1 .. 80) {
 $selTtl[$number] = $value;
}

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Really, the advantages of not having to type 2 more characters ([]) are not worth it, considering the potential problems.

"What should it profit a man, if he should win a flame war, yet lose his cool?"

In reply to Re: Adding scalars but with a twist.. by Joost
in thread Adding scalars but with a twist.. by snappybo

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