allows you to do my $var; $var += 3; without warning as well.
That's interesting. I would have figured it would warn of an uninitialized variable.
This was all I could find:
Use of uninitialized value%s
(W uninitialized) An undefined value was used as if it
were already defined. It was interpreted as a "" or a 0,
but maybe it was a mistake. To suppress this warning
assign a defined value to your variables.
To help you figure out what was undefined, perl tells you
what operation you used the undefined value in. Note,
however, that perl optimizes your program and the
operation displayed in the warning may not necessarily
appear literally in your program. For example, "that $foo"
is usually optimized into "that " . $foo , and the warning
will refer to the concatenation (.) operator, even though
there is no . in your program.
What is the reasoning behind this?
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