In their replies to
counting overlapping patterns, both
Eimi Metamorphoumai and
betterworld (
Update: betterworld's example is list context so that's almost a separate question ;
Update 2: actually no, it's the same issue) submitted code that looked essentially like:
#!/usr/bin/perl
my $foo = "AAAA";
while ($foo =~ /(?=AA)/g) {
print pos $foo;
}
which prints out "012" I am confused as to why this does not cause an infinite loop that continuously prints "0." According to
perlop, following a successful match the value of pos() is set to the position after the end of the matched string, which is where the next iteration of m//g picks up. But since in this case, the matched string is zero-length, why does pos() ever advance? I ask because this seems like a cool trick, but I hesitate to use it since I'm not clear on why it works.
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