If you install Math::Pari, try the function sigma($N,0). That computes the total number of divisors of $N. It requires factorization to compute, but Math::Pari has very fast factorization algorithms.
If N = (p1^a1)*(p2^a2)*...(pR^aR)
then sigma(N,0) = (a1+1)*(a2+1)*...(aR + 1)
This number is usually very small, even for huge N.
If sigma($N,0) is reasonable, you can call divisors($N), which returns a list of all the divisors in order. A simple binary search will find the desired number.
This should be incredibly faster than brute-force countdown searches for large N.
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