So can I avoid it somehow?

Yes, multiply everything by 100 (i.e. deal with cents instead of dollars), and divide by 100 (i.e. convert to dollars) when you print. You won't have the problem, because it doesn't occur for numbers with no decimals, unless they get really big (> 2 billion on a 32 bit system).

>perl -e "$a=0; $a += 0.10 for (1..60); print($a, $/);"
5.99999999999999
>perl -e "$a=0; $a += 10 for (1..60); print($a/100, $/);"
6

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In reply to Re^3: 4253.95 + 0.9 = 4254.84999999999 (need help to interpret internals) by ikegami
in thread 4253.95 + 0.9 = 4254.84999999999 (need help to interpret internals) by jplindstrom

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