This statement is the same as:
$foo = $bar;
$foo =~ s/this/that/;

[download]
But not the same as:
$foo = $bar =~ s/this/that/;
#which will return the result of a substitution  
#because of the lower priority of assignment operator

[download]
To make assignment/substitution in the given order you must
define precedence which can be done with parentheses.


In reply to Re: question of substitution by sh1tn
in thread question of substitution by wannabeboy

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