Here is a simple iterative solution: 
my @factors = (2,3,5);  # Assmue increasing sequence
my $seq_len = 10;

my $index = 0;
foreach my $num (1..$seq_len*$factors[0]) {
   foreach my $factor (@factors) {
      unless ($num % $factor) {
         print "$num ";
         $index++;
         last;
      }
   }
   last if $index >= $seq_len;
}

[download]

-Mark

In reply to Re: Challenge: Another Infinite Lazy List by kvale
in thread Challenge: Another Infinite Lazy List by Limbic~Region

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