"$n * log ($n) - e* log($n) + 0.5 * (log(2*PI)+log($n));"
Stirling's approx is n^ne^{-n}sqrt{2 pi n), so when you take the log, you get nlog(n) - nlog(e) + .5(log(2pi)+log(n)) so it appears one of your terms is incorrect. (Why not use natural log anyway?)
In addition Stirling's gives an asymptotic approximation (the ratio of Stirling's expression to n! is close to 1 for large n; it is not true that the expresion is close to n! for large n.)
chas

In reply to Re: Stirling Approx to N! for large Number? by chas
in thread Stirling Approx to N! for large Number? by monkfan

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