What is undefined is the order of operation. Since ($f + $g++) == ($g++ + $f) this is normally a reasonable assumption, but of course ($f++ + $f) != ($f + $f++).
-- gam3
A picture is worth a thousand words, but takes 200K.

In reply to Re^3: Quantum Weirdness and the Increment Operator by gam3
in thread Quantum Weirdness and the Increment Operator by barrachois

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