note: I am fairly new to perl I have 2 dirs one contains files with sequential filenames ( 12345.dat, 12346.dat, 12347.dat etc..) the other contains similar filenames but with an alpha prefix (A23456.dat, F23457.dat, S23458.dat etc..) I need to create a list that contains the filenames of both dirs -with the newest filenames (higest sequential number regardless of prefix) from both at the top the code i am using (at the moment) for generating my list is: 
opendir THEDIR, "$dirpath" || die "cant open $dirpath !";
@allfiles = grep /^(?:158|159)/,readdir THEDIR; 
closedir THEDIR;
foreach $file (sort { ($b) cmp ($a) } @allfiles) {
print "$file\n";}

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please don't laugh..it took me a LONG time to get that to work. As you can see to make it all go a bit faster i have limited the list to only filenames that start with either 158 or 159. What I need to do is somehow get the contents of the other dir into this list whilst still keeping the newest filenames at the top. ps I'm not asking for a complete script just a few pointers as to how to go about doing it.

In reply to Re^2: multiple dir. grep by Cockneyphil
in thread multiple dir. grep by Cockneyphil

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