Just an observation: 
sub bar {
    print +(caller 0)[3];
}

sub foo { bar }

my $baz = \&foo;
$baz->();

__END__
main::foo

[download]
Until I tried it I didn't think it would work. I guess this works for the same reason the B trick works: that the system knows that a certain subroutine has a name, even when you call it through a reference.

In reply to Re: Finding the name of the target of a coderef by Errto
in thread Finding the name of the target of a coderef by Forsaken

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