I said shorter, I didn't say accurate :). But really, if you presume an overloaded ! that returns something other than perl's true and false values (and that's presuming an awful lot) there's nothing you can do to $y besides examine it in boolean context with if or ?:.

In reply to Re^3: Better expression for $x = !!$y||0 by ysth
in thread Better expression for $x = !!$y||0 by borisz

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