I am trying to work up a regular expression that will capture the file name from the following output. This is to be used in a Perl routine to capture filenames from within a Zip file. (There may be modules that will do what I need, but I cannot install them on the system and because of the way things are run, it would not be a good idea to run them out of my home directory so Extra modules are not an option at this point in time). The data would look like this:
0 Stored 0 0% 04-20-05 08:43 00000000 test 1 2 3.z
+ip
704106 DeflatN 83362 89% 04-04-05 19:00 8e76dc22 file1.dat
What I need to get out would be the file name, so in the first example, it would be "test 1 2 3.zip" and in the second "file1.dat." If I knew there would never be spaces in the names, no problem, but thats not something I can guarantee. Also, file names might be in a mix of upper and lower case. What I have come up with is the following (untested as of yet):
$line =~ /\d\s{1,2}\w{6,7}\s{1,}%\s{2}\d{2}-\d{2}-\d{2}\s{2}\d{2}:\d{2
+}\s{2}\w{8}\s{1,}(\w
{1,}\.\w{3})/;
push @temp, $1;
This would be nested inside of a foreach loop that loops through a temp file containing the data. @temp is then returned back to the main script calling this function. My main question is in looking for a better way to handle the regular expression match.
Any ideas would be welcome. Thanks
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