Hi Monks,

A quickie regarding UK postcode (zip) validation... Is it possible to do the following 3 transformations in one regex or am I asking too much !
Typical UK postcode : LE12 3GX

1.Insert a space before the last 3 characters if there isn't one there already.

2.If the first character of the second part (3 characters as above) is a letter O, swap this to a zero.(this is a very common error)

3. uc() the whole thing.

The final result would pass the validation: /^[A-Z]{1,2}\d{1,2}([A-Z])?\s\d[A-Z]{2}$/

TIA

In reply to UK postcode regex by Anonymous Monk

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