There's no reason to be using
printf here.
print will work just fine. The reason for your error, however, is that the '%' has a special meaning twice. First, it's interpreted as the start of a hash to be interpolated into the string. Your '\' correctly escapes it from this. However, the
printf function then does another round of interpolation, and it expects certain codes in the string, which start with '%'. This time, you use the code '%%' to have it print a literal '%'. Your string that you would pass into
printf would look like "...\%\%..."
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