Try this code. 
Math::BigFloat->new('2187057715053006176499296408615417037129128897214
+238256113698344404908334336944631917741033900096370541032981352897479
+4149028917796716909528358808344846743188026.3358424164688113979341672
+817820980901270335818142717085694006013286169841932603829327703871880
+428990115508942455532934618389216110784616173476066841503276383837003
+379903941568669190776279824783435928019360618178076885689415041227681
+844670764900853378260631999915592273797583721140943359293289412998382
+173652701723265352101625829774791587832397090147942858752926315552361
+783352460136562979750515887006847684035410231950364818914502590711655
+366289482609717574837339905541901751286406418328318293008678171684392
+671085100451990131991851475002542698170815681092942517642292616577517
+786222417104149554986200865059260416692954217421195236361801616322976
+530913722541245775661381844217848774307041052858179134861939621614955
+079372880536990393780066744832735297424321264402399647634986599223736
+661814927327512892111811467257097624814635258985073512630492058901597
+404864371649851510984020115534028021934478375765870460883666269412675
+21');
my $denominator = Math::BigFloat->new('1000000000000000000000000000000
+000000000000000000000000000000000000000000000000000000000000000000000
+0000000000000000000000000000000000000000000000000000000000000');
printf("numerator: %s\n", $numerator + 1 );
printf("numerator: %s\n", $numerator );
printf("denominator: %s\n", $denominator );
my $x = $numerator->copy();
$x->accuracy(10);
print scalar $x->bdiv($denominator), "\n";
$x = $numerator->copy();
$x->accuracy(1000);
print scalar $x->bdiv($denominator), "\n";

[download]
-- gam3
A picture is worth a thousand words, but takes 200K.

In reply to Re: BigFloat Precision by gam3
in thread BigFloat Precision by Willman023

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