Nope, it'll still point to the same underlying hash. 

freebie:~ 702> perl -le '$a={qw(a b)};$b=\%{$a};print "$a\t$b"'
HASH(0x804c844) HASH(0x804c844)

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In reply to Re^3: Copy of an anonymous hash? by Fletch
in thread Copy of an anonymous hash? by Anonymous Monk

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