Code in ??{ .. } is executed to produce a subexpression that then is tested to see if there is a match.

In your case this means that if the subexpression matches, the m// match is done and the code is not called again.

If it doesn't match, the expression is moved forward by one character and tries to match again (which calls the code again, because if you use a code block, you'll likely want to return a different match expression).

It's very likely you can use a more efficient technique here, but that depends on what you actually want to do.

"What should it profit a man, if he should win a flame war, yet lose his cool?"

In reply to Re: ??{ } oddity by Joost
in thread ??{ } oddity by insaniac

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