It's a binary file that I need to edit. The following code works perfectly:

binmode STDIN;
binmode STDOUT;
$/ = \8192; # set "input record separator" to 8KB per read

while (<>) {
tr/\xa7/\x00/;
print;
}


Is it possible to look for more than one hexadecimal number back to back. For example, if I wanted to search the variable for all instances of x31 x33 x39 x37 (not appearing individually but appearing as 1397) how could I replace a set of four hexadecimal numbers with x00 x00 x00 x00 ? And I'm sure this is probably a stupid question, but why does the input record separator need to be set at 8kb? Thanks.

In reply to Re^2: How to open a file in hexadecimal form? by Anonymous Monk
in thread How to open a file in hexadecimal form? by pccode

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