You are passing a reference to tell the constructor to read from its referent.
If you omit the backslash the constructor thinks you want to pass a filehandle or a filename and this will not work for you most likeley because you don't have a filehandle or filename named $intr_html.

'perldoc HTML::TokeParser' tells you more ;-)

In reply to Re: Why do you need to escape a string used as a paramater? by Dietz
in thread Why do you need to escape a string used as a paramater? by awohld

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