Cool. Thanks for replying. :-) A few fixes, then.

You're absolutely right on the runs. Rewrite it as such: 

# Runs
SPAN: for 5 .. 3 -> $span {
    for 1 .. 11 -> $start {
        if all( @cardvals{ $start .. $start + $span } ) {
            $score += $span [*] %cardvals{ $start .. $start + $span};
            last SPAN;
        }
    }
}

[download]
Since %cardvals contains the number of each card, that's the number of times the run should be multiplied by. This also correctly handles 2,3,3,4,4. The span is 3 and the multiplier is 1*2*2, which results in 12.

Update: I'm a little reduce-happy. That should really be:$score += $span *<< %cardvals{ $start .. $start + $span};

You're also absolutely right on the fifteens. There are probably several ways to solve it. There's the brute-force method you used, which is perfectly adequate. However, I think we can use junctions to solve our problem. (Junctions rock, you know.) 

# Fifteens
$score += 2 * all( 15 == [+]@hand{ any( 0 .. 4 ) } };

[download]
I'm not sure that's legal. I've cross-posted it to P6L for @Larry to rip apart.

Update: After japhy's comments, it should probably look something like: 

# Fifteens
$score += 2 * all( 15 == [+]%hand{ any( 0 .. 4 ) } )>>.<num>;

[download]
I'm trying to figure out the correct way to handle the combinations as a single item.
  • In general, if you think something isn't in Perl, try it out, because it usually is. :-)
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In reply to Re^3: Perl6 Contest: Test your Skills by dragonchild
in thread Perl6 Contest: Test your Skills by Limbic~Region

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