Doesn't the $1 notation mean that the value 1 is encoded in the instruction itself (immediate value)?

You are correct. My ASM is rusty.

"There is no shame in being self-taught, only in not trying to learn in the first place." -- Atrus, Myst: The Book of D'ni.

In reply to Re^2: Trinary Operator Semantics by hardburn
in thread Trinary Operator Semantics by hardburn

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