s0o on a 32-bit machine it prints 2147483648
I understand
1 << 63; # returns 2^64
But how is $/ effecting it?
Is it slurping in the highest possible value, and if it cannot get the whole thing it breaks it into pieces?
In reply to Re^2: 64 bit perl
by oopplz
in thread 64 bit perl
by oopplz
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