I now think that while () deparses as for because while (1) is "optimised" (whatever that means) into for(;;) in perl 5.6.1. 

$ perl561 -MO=Deparse -e 'while(1) {1}'
for (;;) {
    '???';
}

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In reply to Re^3: while () by calin
in thread while () by blazar

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