This is for a question that
Dominus posed in the chatterbox.
binround will return the next highest power of two.
the code is a little test script for it. based off the dec2bin recipie from the cookbook.
for ($foo=1; $foo<211;$foo++){
print "$foo ". dec2bin($foo) . " binrounded is ";
$binfoo= (binround ($foo));
print "$binfoo\n";
}
sub binround{
my $str = unpack("B32", pack("N", shift));
$str =~ s/^0+(?=\d)//;
$str=~/^.(.*)/; #first char should always be 1, thanks to above.
$str="1" . "0" x (length ($1)+(($1=~/1/)));
}
sub dec2bin {
my $str = unpack("B32", pack("N", shift));
$str =~ s/^0+(?=\d)//; # otherwise you'll get leading zeros
return $str;
}
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