"How many ways are there to measure 12 balls in groups of two 3 times so that you are guaranteed to know which ball is odd and how it is odd?"

That sentence completely threw me. 12/2 = 6, how can you possibly measure 6 groups with just three measurements? Or maybe it was 12/2*3??? Heres my best attempt, I am sure it can be improved upon :)

What possibile groupings of the 12 balls would allow you to pick the one odd ball after just three measurements?

--
Do not seek to follow in the footsteps of the wise. Seek what they sought. -Basho

In reply to Re: Odd Ball Challenge by greenFox
in thread Odd Ball Challenge by Limbic~Region

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