DB<1> print (2+2)*5; 4 DB<2> print ((2+2)*5); 20 DB<3> print 3*5; 15 DB<4> $foo=(2+2)*5; DB<5> x $foo 0 20
Well, I guess it's some side effect to do with print.
Alex / talexb / Toronto
"Groklaw is the open-source mentality applied to legal research" ~ Linus Torvalds
In reply to Re^2: Perplexing perl problem
by talexb
in thread Perplexing perl problem
by sreejithcyber
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