split operates on \"aString" .. __. As the second argument to split, the .. is actually in scalar context. That's what I can't figure out: \"aString" .. __ doesn't do anything useful in scalar context.
In list context, "a" .. __ would return strings from 'a' to 'zz'; it stops at 'aaa' because 'aaa' is longer than '__'.
In reply to Re: Un-obfuscate me
by chipmunk
in thread Un-obfuscate me
by Anonymous Monk
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