I'm trying to use a regex to catch the >>> of Python's interpreter, but ignore any lines beginning with >>> if preceeded or followed by a >>.

This: 

>>> i = q

[download]
Should become: 
PYTHON_PROMPT i = q

[download]

but this: 

>>> i = q
>> No!

[download]
should stay as is

I've tried: 

s/(?<!^>>[^>])^>>>(?=[^>]*\n)(?!^>>[^>])/PYTHON_PROMPT/mg;

[download]
but it only partially worked.

Also, I'd prefer to avoid $1 if possible, for performance reasons.

Thanks!

janitored by ybiC: Minor format tweaks so that entire node isn't enclosed in <code> tags

In reply to Using a regex to catch interpreters by eastcoastcoder

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