I believe BrowserUK's point is that if foo is just a global subroutine, there is no difference. On the other hand, suppose you had 
package Bar;

sub new { ... }

sub foo {
  state $bar;
  $bar++;
  return $bar;
}

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Then later... 
$bar1 = Bar->new();
$bar2 = Bar->new();

$bar1->foo(); # returns 1, as you would expect
$bar1->foo(); # returns 2, as you would expect
$bar2->foo(); # returns 3, possibly unexpected

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At least this is my understanding. Is this what you meant, BrowserUK?

In reply to Re^3: How will you use state declared variables in Perl6? by jgallagher
in thread How will you use state declared variables in Perl6? by Limbic~Region

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