It would probably help a lot if you didn't refuse to tell us what the different values are.

Try using my $elements = @$arr - 1;. I believe I've seen "N-1" optionally used in the demoninator. I also suspect that $_*$_ will be more accurate than $_**2, but I doubt that would matter enough to cause you to write a node.

- tye        

In reply to Re: standard deviation accuracy question by tye
in thread standard deviation accuracy question by Anonymous Monk

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