This solution is similar to tim's but doesn't use a second intermediate data structure. It uses the flattened hash (from the first step) inline.
# selected stores my @st= ('STORE2','STORE3','STORE5'); # list of stores (doesn't keep duplicates) my %stores= map { %$_ } values %bighash; + foreach my $store ( sort { $stores{$b}[0] <=> $stores{$a}[0] } @st ) { my $products= $stores{$store}; my $earned = shift @$products; + print "STORE: $store EARNING: $earned\n"; foreach my $product ( @$products ) { print join( "," => @$product ), "\n"; } print "\n"; }
As tim says, without a more detailed problem description, it seems that the extra level of nesting in %bighash (set1, set2, etc.) is unnecessary.

--sacked

In reply to Re: Sorting by Hash Slice by sacked
in thread Sorting by Hash Slice by neversaint

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