Dear bart,
Thanks for your correction. I've made update based on your suggestion. Now $name is printed as "data". I've also added function to clarify my intention. But it still gives me: 
Can't open file /files/data.pri:

[download]
Is there anything wrong with this syntax? 
my $file     = "/files/test1.fasta";

[download]
If not, please kindly advice what's the correct one.

---
neversaint and everlastingly indebted.......

In reply to Re^2: How to Open Files from Subdirectory by neversaint
in thread How to Open Files from Subdirectory by neversaint

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