Dear monks, I have an array of ids that may or may not be present in a hash. For each id in the array, I want to print the id in consecutive order, but then print some extra info if it is found in the hash.

I have got my code working so that if the id is present it prints the correct information. However, when I print the values not in the hash, it just prints out all values again ( so in my printed list i get duplicates if a value is present in the hash).

How can I alter my code to print each id only once? Should the elsif bit not pick up everything not in the hash?

Thanks! 

for (my $i=0; $i<@ids; $i++)        {
        my $q;
        while ( my ($key, $value) = each(%hash) ) {
                #print "$key  =>$value\n";
                if ($ids[$i] eq $key)       {
                        print "$key => $value => $extra[$i]\n";
                }
        #if ($ids[$i] ne $key)      {
                elsif ($ids[$i] ne $key) {
                        $q = "$ids[$i]\t $extra[$i]\n";
                }
        }
 
        # PROBLEM IS HERE: IT IS PRINTING ONE OF EACH VALUE, NOT JUST 
+THOSE THAT AREN'T IN THE HASH
        print "$q";
}

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In reply to searching for values in hashes by Anonymous Monk

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