The return value from an empty list when used in a scalar context is undef.

so why should the condition succeed?

perl -e '$empty = (); print ("hi there\n") if \!$empty; __END__ hi there

perl -e '$empty = (); print ("hi there\n") if \!defined($empty);' __END__ hi there

PS: I am using \! to avoid my csh from interepreting it as a special shell character.


In reply to Re: An empty list in boolean context? by sk
in thread An empty list in boolean context? by BUU

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