It seems this should be easy, but I've been banging my head against the wall... I want to call my perl script with 1 parameter and an output from another script, like this: perl script1.pl | perl script2.pl 1 Then I want to store the parameter in a variable and parse the piped input, like so: 
$num = @ARGV[0];
while (<>)
{
   (parser algorithm)
}
print ("$result");

[download]
Well, it doesn't work. I get the error "Can't open 1: no such file or directory" and the parsed output is as if no data has been processed. I assume this is because the 1 is going into <> along with the piped input. Is there some way I can get it out of there before going into my while loop? Also, a curiosity is that the following code behaves slightly differently: 
$num = @ARGV[0];
printf (<>);
while (<>)
{
   (parser algorithm)
}
print( "$result" )

[download]
I still get the error message, but now the parser output is correct. I could just redirect stderr to null and my output is perfect ;) but I'd like to know the "right" way to do this.

In reply to parameters and piped input by trala

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