To crush it down to a one-liner, using glob seemed fastest the most apt:
perl -e 'print "$_\n" for ( sort { -M $a <=> -M $b } glob "/path/\*" )
+;'

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Update: by fastest I was thinking about coding effort rather than meaning to suggest a specific focus on performance.

One world, one people

In reply to Re: How to list files in dir with respect to time ? by anonymized user 468275
in thread How to list files in dir with respect to time ? by swaroop

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