So I learned something about modifying values by reference today. I thought this would work:
sub foo { my $ref = shift; # I expect this change to be visible outside of foo(). $ref = { all => new }; }
I think I see why that doesn't work: I have recreated what "$ref" is, so it no longer is related to the data structure I passed in. However, modifying a value inside of $ref will still be visible outside of the subroutine:
sub foo { my $ref = shift; # Modified value is now visible outside of foo() $ref->{all} = 'new'; }

(Yes, I know explicit return values are generally better style, but modify-by-reference is very handy in some cases).


In reply to Modifying values by reference: what works and what doesn't by markjugg

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