It is not 'obvious' why the string should be bound by x's on both sides if you want the longest string. For n x's, the longest strings would seem to be 
n = 
1 - x
2 - xx
3 - xxx.
4 - xxx.x....
5 - xxx.x.....x......

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in other words, don't forget the trailing non-x caharacters to lengthen the string.

A regex to capture these strings is 

my $regex = '\A' . ('[^x]*x' x $n) .  '[^x]*';
$foo =~ m{ ($regex) }xms;    # PBP orthodoxy :)

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Update: With the problem redefined, the new regex should be retooled to use parsimonious quantifiers to find the shortest strings: 
my $regex = '\A' . ('[^x]*?x' x $n);

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Here I have also left off the last piece of the regex, as it is a noop.

-Mark

In reply to Re: regex finding longest string containing n of $c by kvale
in thread regex finding shortest string containing n of $c by xipho

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