The declared variable is not introduced (is not visible) until after the current statement. Thus, my $x = $x; can be used to initialize a new $x with the value of the old $x, and the expression my $x = 123 and $x == 123 is false unless the old $x happened to have the value 123 .
In reply to Re: Using an undefined value as a hashref
by itub
in thread Using an undefined value as a hashref
by talexb
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